bonsoir
a) (3x+1)² - 4(3x+1)=0
(
( 3 x + 1 ) ( 3 x + 1 - 4 ) = 0
( 3 x + 1 ) ( 3 x - 3 ) = 0
soit 3 x + 1 = 0 et x = - 1/3
soit 3 x - 3 = 0 et x = 1
b) (2x-5)² = 36
( 2 x - 5 )² - 36 = 0
( 2 x - 5 - 6 ) ( 2 x - 5 + 6 ) = 0
( 2 x - 11 ) ( 2 x + 1 ) = 0
x = 11/2 ou - 1/2
c) x² = 9
x = √9 ou - √ 9
x = 3 ou - 3
d) x² = 13
x = √13 ou - √13
e) (2x-5)² = 64
( 2 x - 5 )² - 64 = 0
( 2 x - 5 - 8 ) ( 2 x - 5 + 8 ) = 0
( 2 x - 13 ) ( 2 x + 3 ) = 0
x = 13/2 ou - 3/2
