bonjour
I = (x+3)² - 3(x+3) (x-1)
= (x+3)(x+3-3+x-1)
= (x+3)(2x-1)
J = 4(x-2)² - 9(2x-4)
= 4(x-2)-9*2(x-2)
= 2(x-2)(2x-4-9)
=2(x-2)(2x-13)
(2x-1)² - (5x+2)² = 0
(2x-1-5x-2)(2x-1+5x+2)=0
(-3x - 3)(7x+1)=0
-3x=3 ou 7x = - 1
x = -1 Ou x = -1/7
bonne continuation
