Réponse:
[tex]A = 2 + \frac{8}{9 + \frac{5}{19} } \\ A = 2 + \frac{8}{ \frac{171}{19} + \frac{5}{19} } \\ A = 2 + \frac{8}{ \frac{176}{19} } \\ A = 2 + 8 \times \frac{19}{176} \\ A = 2 + \frac{8 \times 19}{8 \times 22} \\ A = 2 + \frac{19}{22} \\ A = \frac{44}{22} + \frac{19}{22} \\ A = \frac{63}{22} [/tex]
[tex]B = 1 + \frac{ \frac{1}{8} + \frac{3}{4} - \frac{1}{12} }{ \frac{5}{6} + \frac{1}{3} + 2 } \\B = 1 + \frac{ \frac{3}{24} + \frac{18}{24} - \frac{2}{24} }{ \frac{5}{6} + \frac{2}{6} + \frac{12}{6} } \\ B = 1 + \frac{ \frac{19}{24} }{ \frac{19}{6} } \\ B = 1 + \frac{19}{24} \times \frac{6}{19} \\ B = 1 + \frac{19 \times 6}{6 \times 4 \times 19} \\ B = 1 + \frac{1}{4} \\ B = \frac{4}{4} + \frac{1}{4} \\ B = \frac{5}{4} [/tex]
[tex]C = \frac{ \frac{5}{12} }{ \frac{7}{3} \times \frac{8}{15} - \frac{5}{6} } \\ C = \frac{ \frac{5}{12} }{ \frac{56}{45} - \frac{5}{6} } \\ C = \frac{ \frac{5}{12} }{ \frac{112}{90} - \frac{75}{90} } \\ C = \frac{ \frac{5}{12} }{ \frac{37}{90} } \\ C = \frac{5}{12} \times \frac{90}{37} \\ C = \frac{5 \times 15 \times 6}{2 \times 6 \times 37} \\ C = \frac{75}{74} [/tex]
